2x^2=17x-41

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Solution for 2x^2=17x-41 equation: 



2x^2=17x-41

We move all terms to the left:

2x^2-(17x-41)=0

We get rid of parentheses

2x^2-17x+41=0

a = 2; b = -17; c = +41;
Δ = b2-4ac
Δ = -172-4·2·41
Δ = -39
Delta is less than zero, so there is no solution for the equation

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